Flor I. Amador
Instructional Aide (2018)
| Regular pay: | $17,767.42 |
|---|---|
| Overtime pay: | $0.00 |
| Other pay: | $264.59 |
| Total pay: | $18,032.01 |
| Benefits: | $2,800.54 |
| Total pay & benefits: | $20,832.55 |
| Share: |
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| Regular pay: | $17,767.42 |
|---|---|
| Overtime pay: | $0.00 |
| Other pay: | $264.59 |
| Total pay: | $18,032.01 |
| Benefits: | $2,800.54 |
| Total pay & benefits: | $20,832.55 |
| Share: |
Tweet
|