Flor I Amador
Instructional Aide (2019)
| Regular pay: | $20,499.86 |
|---|---|
| Overtime pay: | $0.00 |
| Other pay: | $2,104.37 |
| Total pay: | $22,604.23 |
| Benefits: | $4,010.10 |
| Total pay & benefits: | $26,614.33 |
| Share: |
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| Regular pay: | $20,499.86 |
|---|---|
| Overtime pay: | $0.00 |
| Other pay: | $2,104.37 |
| Total pay: | $22,604.23 |
| Benefits: | $4,010.10 |
| Total pay & benefits: | $26,614.33 |
| Share: |
Tweet
|