Branda Rodriguez
Food Service Worker I (2019)
| Regular pay: | $10,962.39 |
|---|---|
| Overtime pay: | $0.00 |
| Other pay: | $0.00 |
| Total pay: | $10,962.39 |
| Benefits: | $59.40 |
| Total pay & benefits: | $11,021.79 |
| Share: |
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| Regular pay: | $10,962.39 |
|---|---|
| Overtime pay: | $0.00 |
| Other pay: | $0.00 |
| Total pay: | $10,962.39 |
| Benefits: | $59.40 |
| Total pay & benefits: | $11,021.79 |
| Share: |
Tweet
|